Chapter 13

Position Vectors and Geometry

Express AB = b − a, find magnitude |v| = √(x²+y²), and use midpoint and parallel conditions in geometry.

The position vector of a point is its displacement from the origin. Position vectors turn geometry problems into vector algebra.

Vectors between points

If A and B have position vectors a and b, then the vector from A to B is AB = b − a. The magnitude of a vector v = (x, y) is |v| = √(x² + y²), which gives the distance between two points.

Key idea

AB = b − a; |v| = √(x² + y²); midpoint of AB = ½(a + b). Vectors are parallel when one is a scalar multiple of the other.

Parallel and collinear

Two vectors are parallel if one equals a scalar times the other. Points A, B, C are collinear when AB and AC are parallel (they share point A).

Worked example

A = (1, 2), B = (4, 6). Then AB = b − a = (4 − 1, 6 − 2) = (3, 4), and |AB| = √(3² + 4²) = √25 = 5. The midpoint of AB is ½((1, 2) + (4, 6)) = (2.5, 4).

Position vectors also give a neat way to prove that a point divides a line in a given ratio, by writing its position vector as a weighted average of the two endpoints.

Remember

  • Subtract the start point from the end point: AB = b − a.
  • A unit vector is the vector divided by its magnitude.

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