Form 4 · Chapter 5

Geometric Progressions

Explore geometric progressions: find the common ratio, the nth term, the sum of terms and the sum to infinity when |r| < 1.

What is a geometric progression?

A geometric progression (GP) is a sequence in which each term is the previous term multiplied by a fixed number called the common ratio r. For example 3, 6, 12, 24, … has a = 3 and r = 2.

Key formula

nth term: Tn = a rn−1
Sum of n terms: Sn = a(rn − 1)/(r − 1), r ≠ 1
Sum to infinity: S = a/(1 − r), valid only when |r| < 1.

Finding a term and the ratio

The common ratio is any term divided by the one before it: r = T2 ÷ T1. Then the nth-term formula gives any term.

  • For 5, 10, 20, …: r = 2, so T5 = 5 × 24 = 80.
  • If T2 = 6 and T4 = 54, then r2 = 54/6 = 9, so r = 3.

Worked example

A GP has a = 3 and r = 2. Find T4 and S5.

T4 = 3 × 23 = 3 × 8 = 24.

S5 = 3(25 − 1)/(2 − 1) = 3(32 − 1)/1 = 93.

Sum to infinity

When |r| < 1 the terms shrink towards zero and the sum settles on a finite value. For 8 + 4 + 2 + …, a = 8 and r = 1/2, so S = 8/(1 − 1/2) = 16.

Remember

  • S exists only when −1 < r < 1.
  • The power in Tn is rn−1, not rn.
  • r can be a fraction or negative.

Stuck on this topic? A verified JomKelas tutor can walk you through it.

Find a verified tutor