Key quantities
Distance is the total path length (a scalar). Displacement is the straight-line change in position with direction (a vector). Speed is distance ÷ time; velocity is displacement ÷ time and has direction. Acceleration is the rate of change of velocity.
Key formula
The three equations of motion (constant acceleration):
v = u + at
s = ut + ½at²
v² = u² + 2as
where u = initial velocity, v = final velocity, a = acceleration, t = time, s = displacement.
Acceleration
Acceleration a = (v − u) ÷ t, with unit m s⁻². A negative value means deceleration (slowing down). If velocity is constant, acceleration is zero.
Worked example
A car starts from rest (u = 0) and accelerates at 2 m s⁻² for 6 s. Find its final velocity and the distance travelled.
v = u + at = 0 + (2)(6) = 12 m s⁻¹.
s = ut + ½at² = 0 + ½(2)(6²) = ½ × 2 × 36 = 36 m.
Using v² = u² + 2as
This equation is useful when time is not given. For a car slowing from 20 m s⁻¹ to rest over 40 m: 0 = 20² + 2a(40), so a = −400 ÷ 80 = −5 m s⁻² (a deceleration).
Remember
- Choose the equation that matches the quantities you know.
- Keep a consistent direction as positive throughout.
- Deceleration is a negative acceleration.